X^2+20x-11200=0

Solution for X^2+20x-11200=0 equation:

X^2+20X-11200=0

a = 1; b = 20; c = -11200;
Δ = b2-4ac
Δ = 202-4·1·(-11200)
Δ = 45200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45200}=\sqrt{400*113}=\sqrt{400}*\sqrt{113}=20\sqrt{113}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{113}}{2*1}=\frac{-20-20\sqrt{113}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{113}}{2*1}=\frac{-20+20\sqrt{113}}{2}
$